17x+285=x^2

Solution for 17x+285=x^2 equation:

17x+285=x^2

We move all terms to the left:

17x+285-(x^2)=0

determiningTheFunctionDomain
-x^2+17x+285=0

We add all the numbers together, and all the variables

-1x^2+17x+285=0

a = -1; b = 17; c = +285;
Δ = b2-4ac
Δ = 172-4·(-1)·285
Δ = 1429
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(17)-\sqrt{1429}}{2*-1}=\frac{-17-\sqrt{1429}}{-2}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(17)+\sqrt{1429}}{2*-1}=\frac{-17+\sqrt{1429}}{-2}
$